{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ x^2 $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ x = \\dfrac{-b \\pm \\sqrt{b^2 - 4ac}}{2a} $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ y = a + b x_{ij}^2 $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ \\sum_{i=0}^{n}(x_i^2 + y_j^3) $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "使用 \\frac{分母}{分子}，或\\cfrac{分母}{分子}\n",
    "$$\\cfrac{1}{3} - \\frac{x_i^2}{y_j^3}$$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ \\left[ \\begin{array} {cccc}\n",
    "X_1&Y_1^2\\\\\n",
    "X_2 & Y_2^2\\\\\n",
    "\\ldots \\\\\n",
    "X_n&Y_n^2\n",
    "\\end{array} \\right] $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ f(x_1,x_2,\\ldots,x_i) = x_1+x_2+\\cdots + x_i $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "$$ x + \\left(y^2 + \\frac{x^2+z}{1+z^2}\\right)  $$"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": []
  }
 ],
 "metadata": {
  "kernelspec": {
   "display_name": "Python 3",
   "language": "python",
   "name": "python3"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 3
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython3",
   "version": "3.6.4"
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 },
 "nbformat": 4,
 "nbformat_minor": 2
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